Learn on PengiCalifornia Reveal Math, Algebra 1Unit 1: Using Expressions and Equations

1-3 Solving Equations in One Variable

In this Grade 9 lesson from California Reveal Math Algebra 1, students learn to solve one-variable equations using the properties of equality, including addition, subtraction, multiplication, and division. The lesson covers writing and solving equations with fractions, grouping symbols such as parentheses and the distributive property, and identifying special cases like equations with no solution or infinitely many solutions (identities). Students also explore constraints as conditions a solution must satisfy and use algebra tiles to model and reason about equation-solving.

Section 1

Solving Equations

Property

We solve an equation by undoing in reverse order the operations performed on the variable. We can think of any string of terms as a sum, where the ++ and - symbols tell us the sign of the term that follows. To solve, first add or subtract terms to isolate the variable term, then multiply or divide to find the variable's value.

Examples

  • To solve 124x=812 - 4x = -8, first subtract 12 from both sides to get 4x=20-4x = -20. Then divide by 4-4 to find x=5x = 5.
  • To solve 3y+7=22-3y + 7 = 22, first subtract 7 from both sides to get 3y=15-3y = 15. Then divide by 3-3 to get y=5y = -5.
  • To solve x53=2\frac{x-5}{3} = -2, first multiply both sides by 3 to get x5=6x-5 = -6. Then add 5 to both sides to find x=1x = -1.

Explanation

Solving an equation is like being a detective to find the variable's hidden value. You reverse the equation's steps, undoing each operation one by one until the variable is alone on one side of the equals sign.

Section 2

Solving Equations with Grouping Symbols

Property

When equations contain symbols of inclusion such as parentheses, use the Distributive Property to eliminate them first. Then combine like terms and apply inverse operations to solve.

Examples

  • Solve a+4(2a+3)=39a + 4(2a + 3) = 39. Distribute the 4: a+8a+12=39a + 8a + 12 = 39. Combine like terms: 9a+12=399a + 12 = 39. Solve: 9a=279a = 27, so a=3a = 3.
  • To solve 6(c3)=246(c - 3) = 24, first distribute the 6: 6c18=246c - 18 = 24. Then add 18 to both sides: 6c=426c = 42. The solution is c=7c = 7.
  • In 3(x+5)+2x=353(x + 5) + 2x = 35, distribute the 3 to get 3x+15+2x=353x + 15 + 2x = 35. Combine terms: 5x+15=355x + 15 = 35. Solve to find x=4x = 4.

Explanation

Parentheses in an equation are like a locked treasure chest! You have to 'distribute' the number outside to every item inside to unlock it. This unwraps the equation, letting you combine terms and solve for the hidden variable. Multiplying everything inside the parentheses is the key that opens up the problem.

Section 3

Special Cases: Identities and No-Solution Equations

Property

When solving a linear equation, one of three outcomes is possible:

One Solution: The variable isolates to a single value, e.g., x=ax = a.

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Solving Equations

Property

We solve an equation by undoing in reverse order the operations performed on the variable. We can think of any string of terms as a sum, where the ++ and - symbols tell us the sign of the term that follows. To solve, first add or subtract terms to isolate the variable term, then multiply or divide to find the variable's value.

Examples

  • To solve 124x=812 - 4x = -8, first subtract 12 from both sides to get 4x=20-4x = -20. Then divide by 4-4 to find x=5x = 5.
  • To solve 3y+7=22-3y + 7 = 22, first subtract 7 from both sides to get 3y=15-3y = 15. Then divide by 3-3 to get y=5y = -5.
  • To solve x53=2\frac{x-5}{3} = -2, first multiply both sides by 3 to get x5=6x-5 = -6. Then add 5 to both sides to find x=1x = -1.

Explanation

Solving an equation is like being a detective to find the variable's hidden value. You reverse the equation's steps, undoing each operation one by one until the variable is alone on one side of the equals sign.

Section 2

Solving Equations with Grouping Symbols

Property

When equations contain symbols of inclusion such as parentheses, use the Distributive Property to eliminate them first. Then combine like terms and apply inverse operations to solve.

Examples

  • Solve a+4(2a+3)=39a + 4(2a + 3) = 39. Distribute the 4: a+8a+12=39a + 8a + 12 = 39. Combine like terms: 9a+12=399a + 12 = 39. Solve: 9a=279a = 27, so a=3a = 3.
  • To solve 6(c3)=246(c - 3) = 24, first distribute the 6: 6c18=246c - 18 = 24. Then add 18 to both sides: 6c=426c = 42. The solution is c=7c = 7.
  • In 3(x+5)+2x=353(x + 5) + 2x = 35, distribute the 3 to get 3x+15+2x=353x + 15 + 2x = 35. Combine terms: 5x+15=355x + 15 = 35. Solve to find x=4x = 4.

Explanation

Parentheses in an equation are like a locked treasure chest! You have to 'distribute' the number outside to every item inside to unlock it. This unwraps the equation, letting you combine terms and solve for the hidden variable. Multiplying everything inside the parentheses is the key that opens up the problem.

Section 3

Special Cases: Identities and No-Solution Equations

Property

When solving a linear equation, one of three outcomes is possible:

One Solution: The variable isolates to a single value, e.g., x=ax = a.