Learn on PengiCalifornia Reveal Math, Algebra 1Unit 8: Exponential Functions

8-3 Writing Equations for Exponential Functions

In this Grade 9 lesson from California Reveal Math Algebra 1, students learn to write equations for exponential functions in the form y = ab^x using two points, a graph, or a written description. The lesson covers identifying the initial value and common ratio, solving systems of equations by substitution, and distinguishing between exponential growth and decay. Students also apply these skills to real-world contexts such as population growth and compound interest.

Section 1

Finding a and b from Two Points

Property

To find an exponential function f(x)=abxf(x) = ab^x through two points:

  1. Use the coordinates of the points to write two equations in aa and bb.
  1. Divide one equation by the other to eliminate aa.

Section 2

Identifying Exponential Growth vs. Decay from Context

Property

A situation represents exponential growth when the quantity increases over time and exponential decay when the quantity decreases over time.

Use the clues below to identify the type and select the correct formula:

Section 3

Modeling Exponential Growth and Decay: y = a(1 ± r)^t

Property

The function

P(t)=P0btP(t) = P_0 b^t
models exponential growth and decay.

  • P0=P(0)P_0 = P(0) is the initial value of PP;
  • bb is the growth or decay factor.

(a) If b>1b > 1, then P(t)P(t) is increasing, and b=1+rb = 1 + r, where rr represents percent increase.
(b) If 0<b<10 < b < 1, then P(t)P(t) is decreasing, and b=1rb = 1 - r, where rr represents percent decrease.

Examples

  • A town with 1,000 people grows by 5% per year. Its population is modeled by P(t)=1000(1+0.05)t=1000(1.05)tP(t) = 1000(1+0.05)^t = 1000(1.05)^t.
  • A 50mg dose of medicine decreases in the body by 20% each hour. The amount remaining is A(t)=50(10.20)t=50(0.8)tA(t) = 50(1-0.20)^t = 50(0.8)^t.
  • The value of an investment doubles every 10 years. If the initial investment is 500 dollars, the growth factor is 2, and the value is V(t)=500(2)t/10V(t) = 500(2)^{t/10}.

Explanation

This function describes something that multiplies by the same amount over time. If the multiplier (b) is bigger than 1, it grows. If it's between 0 and 1, it shrinks. It's all about repeated multiplication!

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Finding a and b from Two Points

Property

To find an exponential function f(x)=abxf(x) = ab^x through two points:

  1. Use the coordinates of the points to write two equations in aa and bb.
  1. Divide one equation by the other to eliminate aa.

Section 2

Identifying Exponential Growth vs. Decay from Context

Property

A situation represents exponential growth when the quantity increases over time and exponential decay when the quantity decreases over time.

Use the clues below to identify the type and select the correct formula:

Section 3

Modeling Exponential Growth and Decay: y = a(1 ± r)^t

Property

The function

P(t)=P0btP(t) = P_0 b^t
models exponential growth and decay.

  • P0=P(0)P_0 = P(0) is the initial value of PP;
  • bb is the growth or decay factor.

(a) If b>1b > 1, then P(t)P(t) is increasing, and b=1+rb = 1 + r, where rr represents percent increase.
(b) If 0<b<10 < b < 1, then P(t)P(t) is decreasing, and b=1rb = 1 - r, where rr represents percent decrease.

Examples

  • A town with 1,000 people grows by 5% per year. Its population is modeled by P(t)=1000(1+0.05)t=1000(1.05)tP(t) = 1000(1+0.05)^t = 1000(1.05)^t.
  • A 50mg dose of medicine decreases in the body by 20% each hour. The amount remaining is A(t)=50(10.20)t=50(0.8)tA(t) = 50(1-0.20)^t = 50(0.8)^t.
  • The value of an investment doubles every 10 years. If the initial investment is 500 dollars, the growth factor is 2, and the value is V(t)=500(2)t/10V(t) = 500(2)^{t/10}.

Explanation

This function describes something that multiplies by the same amount over time. If the multiplier (b) is bigger than 1, it grows. If it's between 0 and 1, it shrinks. It's all about repeated multiplication!