Learn on PengiAoPS: Introduction to Algebra (AMC 8 & 10)Chapter 10: Quadratic Equations - Part 1

Lesson 2: Factoring Quadratics I

In this Grade 4 AoPS Introduction to Algebra lesson, students learn how to factor quadratic expressions of the form x² + bx + c by finding two numbers r and s such that r + s equals the linear coefficient and rs equals the constant term. The lesson covers identifying roots and zeros of a quadratic equation by rewriting it as a product of binomials and applying the zero-product property. Part of Chapter 10 on Quadratic Equations, this lesson builds problem-solving strategies for AMC 8 and AMC 10 competition math.

Section 1

Factor Quadratics with c = 0

Property

When c=0c = 0, the quadratic x2+bxx^2 + bx can be factored by taking out the common factor xx:

x2+bx=x(x+b)x^2 + bx = x(x + b)

Section 2

Factor Trinomials of the Form x2+bx+cx^2 + bx + c

Property

To factor a trinomial of the form x2+bx+cx^2 + bx + c, we need two factors (x+m)(x + m) and (x+n)(x + n) where the two numbers mm and nn multiply to cc and add to bb.

How to factor trinomials of the form x2+bx+cx^2 + bx + c

  1. Write the factors as two binomials with first terms xx: (x)(x)(x \quad)(x \quad).
  2. Find two numbers mm and nn that multiply to cc, mn=cm \cdot n = c, and add to bb, m+n=bm + n = b.
  3. Use mm and nn as the last terms of the factors.
  4. Check by multiplying the factors.

Strategy for Determining Signs
When cc is positive, mm and nn have the same sign as bb.

  • If bb is positive, mm and nn are positive. Example: x2+5x+6=(x+2)(x+3)x^2 + 5x + 6 = (x+2)(x+3).
  • If bb is negative, mm and nn are negative. Example: x26x+8=(x4)(x2)x^2 - 6x + 8 = (x-4)(x-2).

Section 3

Factor Perfect Square Trinomials

Property

If aa and bb are real numbers, the perfect square trinomials pattern is as follows:

a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a+b)^2
a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a-b)^2
To use this pattern, first verify that the trinomial fits.
Check if the first term is a perfect square (a2a^2) and the last term is a perfect square (b2b^2).
Then, check if the middle term is twice their product (2ab2ab).
If it matches, write the square of the binomial (a+b)2(a+b)^2 or (ab)2(a-b)^2.

Examples

  • To factor 25x2+30x+925x^2 + 30x + 9, recognize it as (5x)2+2(5x)(3)+32(5x)^2 + 2(5x)(3) + 3^2. This fits the pattern a2+2ab+b2a^2+2ab+b^2, so the factored form is (5x+3)2(5x+3)^2.
  • To factor 49y242y+949y^2 - 42y + 9, identify it as (7y)22(7y)(3)+32(7y)^2 - 2(7y)(3) + 3^2. This matches the pattern a22ab+b2a^2-2ab+b^2, so the factored form is (7y3)2(7y-3)^2.

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Factor Quadratics with c = 0

Property

When c=0c = 0, the quadratic x2+bxx^2 + bx can be factored by taking out the common factor xx:

x2+bx=x(x+b)x^2 + bx = x(x + b)

Section 2

Factor Trinomials of the Form x2+bx+cx^2 + bx + c

Property

To factor a trinomial of the form x2+bx+cx^2 + bx + c, we need two factors (x+m)(x + m) and (x+n)(x + n) where the two numbers mm and nn multiply to cc and add to bb.

How to factor trinomials of the form x2+bx+cx^2 + bx + c

  1. Write the factors as two binomials with first terms xx: (x)(x)(x \quad)(x \quad).
  2. Find two numbers mm and nn that multiply to cc, mn=cm \cdot n = c, and add to bb, m+n=bm + n = b.
  3. Use mm and nn as the last terms of the factors.
  4. Check by multiplying the factors.

Strategy for Determining Signs
When cc is positive, mm and nn have the same sign as bb.

  • If bb is positive, mm and nn are positive. Example: x2+5x+6=(x+2)(x+3)x^2 + 5x + 6 = (x+2)(x+3).
  • If bb is negative, mm and nn are negative. Example: x26x+8=(x4)(x2)x^2 - 6x + 8 = (x-4)(x-2).

Section 3

Factor Perfect Square Trinomials

Property

If aa and bb are real numbers, the perfect square trinomials pattern is as follows:

a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a+b)^2
a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a-b)^2
To use this pattern, first verify that the trinomial fits.
Check if the first term is a perfect square (a2a^2) and the last term is a perfect square (b2b^2).
Then, check if the middle term is twice their product (2ab2ab).
If it matches, write the square of the binomial (a+b)2(a+b)^2 or (ab)2(a-b)^2.

Examples

  • To factor 25x2+30x+925x^2 + 30x + 9, recognize it as (5x)2+2(5x)(3)+32(5x)^2 + 2(5x)(3) + 3^2. This fits the pattern a2+2ab+b2a^2+2ab+b^2, so the factored form is (5x+3)2(5x+3)^2.
  • To factor 49y242y+949y^2 - 42y + 9, identify it as (7y)22(7y)(3)+32(7y)^2 - 2(7y)(3) + 3^2. This matches the pattern a22ab+b2a^2-2ab+b^2, so the factored form is (7y3)2(7y-3)^2.