Learn on PengienVision, Algebra 2Chapter 6: Exponential and Logarithmic Functions

Lesson 3: Logarithms

In this Grade 11 enVision Algebra 2 lesson, students learn what logarithms are and how to evaluate them by understanding that a logarithm is the inverse of exponentiation. Students practice converting between exponential form and logarithmic form, evaluating expressions such as log base 5 of 125, and identifying when a logarithmic expression is undefined. The lesson also introduces common logarithms and natural logarithms as part of Chapter 6 on Exponential and Logarithmic Functions.

Section 1

Definition of Logarithm

Property

For b>0b > 0, b1b \neq 1, the base bb logarithm of xx, written logbx\log_b x, is the exponent to which bb must be raised in order to yield xx. This gives the following conversion equations:

y=logbxif and only ifx=byy = \log_b x \quad \text{if and only if} \quad x = b^y

Examples

  • The logarithmic statement log381=4\log_3 81 = 4 is the same as asking "what power of 3 equals 81?", which is answered by the exponential statement 34=813^4 = 81.
  • To solve the equation 10x=10010^x = 100, you can rewrite it in logarithmic form as x=log10100x = \log_{10} 100, which means x=2x = 2.
  • The expression log71\log_7 1 asks "7 to what power equals 1?" Since any number to the power of 0 is 1, log71=0\log_7 1 = 0.

Explanation

A logarithm answers the question: "What exponent do I need?" It undoes an exponential function, allowing you to solve for a variable that is stuck in the exponent. It's the key to unlocking those tricky exponential equations.

Section 2

Evaluate Logarithmic Functions

Property

We can solve and evaluate logarithmic equations by using the technique of converting the equation to its equivalent exponential equation. To find the exact value of a logarithm like logbN\log_b N, you can set the expression equal to xx (so logbN=x\log_b N = x) and then convert it into the exponential equation bx=Nb^x = N to solve for xx.

Examples

  • To find the value of xx in logx81=2\log_x 81 = 2, convert to exponential form: x2=81x^2 = 81. Since the base must be positive, x=9x=9.
  • To find the value of xx in log2x=5\log_2 x = 5, convert to exponential form: 25=x2^5 = x. Therefore, x=32x=32.
  • To find the exact value of log5125\log_5 \frac{1}{25}, set it to xx. log5125=x\log_5 \frac{1}{25} = x becomes 5x=1255^x = \frac{1}{25}. Since 125=52\frac{1}{25} = 5^{-2}, we find x=2x = -2.

Explanation

Evaluating a logarithm means finding the exponent. By asking, 'What power do I raise the base to get the number?', you are setting up the problem. Converting to an exponential equation is the formal way to solve for that unknown exponent.

Section 3

Base 10 logarithms

Property

Base 10 logarithms are called common logarithms.

The subscript 10 is often omitted, so that logx\log x is understood to mean log10x\log_{10} x. To evaluate a base 10 logarithm, we use the LOG key on a calculator.

Examples

  • To find log101000\log_{10} 1000, we know 103=100010^3=1000, so log1000=3\log 1000 = 3.
  • To approximate log350\log 350, use a calculator: log3502.5441\log 350 \approx 2.5441. This means 102.544135010^{2.5441} \approx 350.
  • To solve 10x=1210^x = 12, we rewrite it as x=log12x = \log 12. Using a calculator, x1.0792x \approx 1.0792.

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Definition of Logarithm

Property

For b>0b > 0, b1b \neq 1, the base bb logarithm of xx, written logbx\log_b x, is the exponent to which bb must be raised in order to yield xx. This gives the following conversion equations:

y=logbxif and only ifx=byy = \log_b x \quad \text{if and only if} \quad x = b^y

Examples

  • The logarithmic statement log381=4\log_3 81 = 4 is the same as asking "what power of 3 equals 81?", which is answered by the exponential statement 34=813^4 = 81.
  • To solve the equation 10x=10010^x = 100, you can rewrite it in logarithmic form as x=log10100x = \log_{10} 100, which means x=2x = 2.
  • The expression log71\log_7 1 asks "7 to what power equals 1?" Since any number to the power of 0 is 1, log71=0\log_7 1 = 0.

Explanation

A logarithm answers the question: "What exponent do I need?" It undoes an exponential function, allowing you to solve for a variable that is stuck in the exponent. It's the key to unlocking those tricky exponential equations.

Section 2

Evaluate Logarithmic Functions

Property

We can solve and evaluate logarithmic equations by using the technique of converting the equation to its equivalent exponential equation. To find the exact value of a logarithm like logbN\log_b N, you can set the expression equal to xx (so logbN=x\log_b N = x) and then convert it into the exponential equation bx=Nb^x = N to solve for xx.

Examples

  • To find the value of xx in logx81=2\log_x 81 = 2, convert to exponential form: x2=81x^2 = 81. Since the base must be positive, x=9x=9.
  • To find the value of xx in log2x=5\log_2 x = 5, convert to exponential form: 25=x2^5 = x. Therefore, x=32x=32.
  • To find the exact value of log5125\log_5 \frac{1}{25}, set it to xx. log5125=x\log_5 \frac{1}{25} = x becomes 5x=1255^x = \frac{1}{25}. Since 125=52\frac{1}{25} = 5^{-2}, we find x=2x = -2.

Explanation

Evaluating a logarithm means finding the exponent. By asking, 'What power do I raise the base to get the number?', you are setting up the problem. Converting to an exponential equation is the formal way to solve for that unknown exponent.

Section 3

Base 10 logarithms

Property

Base 10 logarithms are called common logarithms.

The subscript 10 is often omitted, so that logx\log x is understood to mean log10x\log_{10} x. To evaluate a base 10 logarithm, we use the LOG key on a calculator.

Examples

  • To find log101000\log_{10} 1000, we know 103=100010^3=1000, so log1000=3\log 1000 = 3.
  • To approximate log350\log 350, use a calculator: log3502.5441\log 350 \approx 2.5441. This means 102.544135010^{2.5441} \approx 350.
  • To solve 10x=1210^x = 12, we rewrite it as x=log12x = \log 12. Using a calculator, x1.0792x \approx 1.0792.