Property
The standard form of the equation of a hyperbola with center (0,0) is
a2x2−b2y2=1ora2y2−b2x2=1 For a2x2−b2y2=1, the transverse axis is on the x-axis, it opens left and right, vertices are (±a,0), and asymptotes are y=±abx. For a2y2−b2x2=1, the transverse axis is on the y-axis, it opens up and down, vertices are (0,±a), and asymptotes are y=±bax.
To graph: Write the equation in standard form. Find vertices from the positive term's denominator, a2. Sketch a rectangle using points (±a,0) and (0,±b) (or vice versa depending on orientation). Draw asymptotes through the rectangle's diagonals. Draw the branches from the vertices, approaching the asymptotes.
Examples
- To graph 16x2−9y2=1, note the center is (0,0) and it opens horizontally since x2 is positive. The vertices are (±4,0). The guide rectangle uses (0,±3), giving asymptotes y=±43x.
- To graph 64y2−25x2=1, note the center is (0,0) and it opens vertically since y2 is positive. The vertices are (0,±8). The guide rectangle uses (±5,0), giving asymptotes y=±58x.
- To graph 4y2−25x2=100, first divide by 100 to get 25y2−4x2=1. This is a vertical hyperbola with vertices at (0,±5) and asymptotes y=±25x.
Explanation
This equation describes a hyperbola centered at the origin. The term with the positive coefficient (x2 or y2) tells you if it opens horizontally or vertically. The values a and b create a guide rectangle for sketching the asymptotes.