Learn on PengiThe Art of Problem Solving: Prealgebra (AMC 8)Chapter 5: Equations and Inequalities

Lesson 4: Word Problems

In this Grade 4 lesson from The Art of Problem Solving: Prealgebra (AMC 8), students learn a structured method for translating word problems into algebraic equations by assigning variables to unknown quantities and expressing multiple unknowns in terms of a single variable. Lessons cover setting up and solving linear equations from verbal descriptions, including problems with fractions, sums, and real-world scenarios. Students also practice checking solutions to confirm their equations correctly represent the original problem.

Section 1

Defining Variables and Equations

Property

  1. It is very important to specify precisely what the variable represents. The variable must stand for a number. For example, use ww for "Lima's weight," not for "Lima."
  2. Although the equation includes the variable, the two sides of the equation may actually be expressions for some other quantity, such as a ratio.

Examples

  • To describe "Sam is 5 years older than Tim," define SS as "Sam's age in years" and TT as "Tim's age in years." The correct equation is S=T+5S = T + 5. Defining variables just as "Sam" and "Tim" would be unclear.
  • If a school has a student-to-teacher ratio of 15 to 1 and there are 450 students, we want to find the number of teachers, tt. The equation 450t=151\frac{450}{t} = \frac{15}{1} is about the ratio, not the number of teachers itself.

Section 2

Problems with Two Unknowns

Property

When a problem involves two unknown quantities, name the first unknown with a variable (e.g., nn).
Then, read the problem to find the relationship between the two unknowns and write an expression for the second unknown using the same variable (e.g., n+5n+5 or 2n102n-10).
Finally, form an equation that relates both unknowns and solve.

Examples

  • One number is ten more than another. Their sum is 52. Find the numbers. Let the first number be nn. The second is n+10n+10. The equation is n+(n+10)=52n + (n+10) = 52. This simplifies to 2n=422n=42, so n=21n=21. The numbers are 21 and 31.
  • The sum of two numbers is negative twenty. One number is six less than the other. Find the numbers. Let the first number be xx. The second is x6x-6. The equation is x+(x6)=20x + (x-6) = -20. This simplifies to 2x=142x = -14, so x=7x=-7. The numbers are -7 and -13.

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Defining Variables and Equations

Property

  1. It is very important to specify precisely what the variable represents. The variable must stand for a number. For example, use ww for "Lima's weight," not for "Lima."
  2. Although the equation includes the variable, the two sides of the equation may actually be expressions for some other quantity, such as a ratio.

Examples

  • To describe "Sam is 5 years older than Tim," define SS as "Sam's age in years" and TT as "Tim's age in years." The correct equation is S=T+5S = T + 5. Defining variables just as "Sam" and "Tim" would be unclear.
  • If a school has a student-to-teacher ratio of 15 to 1 and there are 450 students, we want to find the number of teachers, tt. The equation 450t=151\frac{450}{t} = \frac{15}{1} is about the ratio, not the number of teachers itself.

Section 2

Problems with Two Unknowns

Property

When a problem involves two unknown quantities, name the first unknown with a variable (e.g., nn).
Then, read the problem to find the relationship between the two unknowns and write an expression for the second unknown using the same variable (e.g., n+5n+5 or 2n102n-10).
Finally, form an equation that relates both unknowns and solve.

Examples

  • One number is ten more than another. Their sum is 52. Find the numbers. Let the first number be nn. The second is n+10n+10. The equation is n+(n+10)=52n + (n+10) = 52. This simplifies to 2n=422n=42, so n=21n=21. The numbers are 21 and 31.
  • The sum of two numbers is negative twenty. One number is six less than the other. Find the numbers. Let the first number be xx. The second is x6x-6. The equation is x+(x6)=20x + (x-6) = -20. This simplifies to 2x=142x = -14, so x=7x=-7. The numbers are -7 and -13.