Learn on PengiBig Ideas Math, Algebra 1Chapter 8: Graphing Quadratic Functions

Lesson 5: Using Intercept Form

Property If the product of two numbers is zero, then one (or both) of the numbers must be zero. Using symbols,.

Section 1

Zero-factor principle

Property

If the product of two numbers is zero, then one (or both) of the numbers must be zero. Using symbols,

If AB=0AB = 0, then either A=0A = 0 or B=0B = 0.

Examples

  • To solve (x7)(x+2)=0(x - 7)(x + 2) = 0, we set each factor to zero. This gives us x7=0x - 7 = 0 or x+2=0x + 2 = 0, so the solutions are x=7x = 7 and x=2x = -2.
  • If y(y10)=0y(y - 10) = 0, then either y=0y = 0 or y10=0y - 10 = 0. The two solutions for the equation are y=0y = 0 and y=10y = 10.
  • Given (2a+1)(a5)=0(2a + 1)(a - 5) = 0, we solve 2a+1=02a + 1 = 0 to get a=12a = -\frac{1}{2}, and we solve a5=0a - 5 = 0 to get a=5a = 5.

Section 2

Writing Quadratic Functions in Intercept Form

Property

If a quadratic function has zeros at x=px = p and x=qx = q, then it can be written in intercept form as f(x)=a(xp)(xq)f(x) = a(x - p)(x - q) where a0a \neq 0.

Examples

Section 3

Factoring Cubic Polynomials for Zeros

Property

To find zeros of a cubic polynomial f(x)=a(xp)(xq)(xr)f(x) = a(x - p)(x - q)(x - r), set each factor equal to zero: (xp)=0(x - p) = 0, (xq)=0(x - q) = 0, and (xr)=0(x - r) = 0. For cubic polynomials not in factored form, factor completely first, then apply the zero-product property.

Examples

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Zero-factor principle

Property

If the product of two numbers is zero, then one (or both) of the numbers must be zero. Using symbols,

If AB=0AB = 0, then either A=0A = 0 or B=0B = 0.

Examples

  • To solve (x7)(x+2)=0(x - 7)(x + 2) = 0, we set each factor to zero. This gives us x7=0x - 7 = 0 or x+2=0x + 2 = 0, so the solutions are x=7x = 7 and x=2x = -2.
  • If y(y10)=0y(y - 10) = 0, then either y=0y = 0 or y10=0y - 10 = 0. The two solutions for the equation are y=0y = 0 and y=10y = 10.
  • Given (2a+1)(a5)=0(2a + 1)(a - 5) = 0, we solve 2a+1=02a + 1 = 0 to get a=12a = -\frac{1}{2}, and we solve a5=0a - 5 = 0 to get a=5a = 5.

Section 2

Writing Quadratic Functions in Intercept Form

Property

If a quadratic function has zeros at x=px = p and x=qx = q, then it can be written in intercept form as f(x)=a(xp)(xq)f(x) = a(x - p)(x - q) where a0a \neq 0.

Examples

Section 3

Factoring Cubic Polynomials for Zeros

Property

To find zeros of a cubic polynomial f(x)=a(xp)(xq)(xr)f(x) = a(x - p)(x - q)(x - r), set each factor equal to zero: (xp)=0(x - p) = 0, (xq)=0(x - q) = 0, and (xr)=0(x - r) = 0. For cubic polynomials not in factored form, factor completely first, then apply the zero-product property.

Examples