Learn on PengiAoPS: Introduction to Algebra (AMC 8 & 10)Chapter 5: Multi-Variable Linear Equations

Lesson 6: More Variables

In this Grade 4 AMC Math lesson from AoPS: Introduction to Algebra, students learn how to solve systems of three-variable linear equations using substitution and elimination to reduce them to simpler two-variable systems. Working through problems like solving for x, y, and z simultaneously, students apply techniques such as multiplying equations to match coefficients and strategically eliminating variables step by step. This lesson is part of Chapter 5 on Multi-Variable Linear Equations and also introduces setting up multi-variable equations from word problems involving unknown quantities.

Section 1

Coefficient Matching for Linear Expressions

Property

If two linear expressions are equal for all values of a variable, then their corresponding coefficients must be equal:

If ax+b=cx+dax + b = cx + d for all values of xx, then a=ca = c and b=db = d

Section 2

Solving 3x3 Systems by Substitution

Property

To solve a system of three equations with three variables using substitution, follow these steps:

  1. Solve one of the equations for one variable in terms of the other two.
  2. Substitute the resulting expression into the other two equations. This creates a new system of two equations with two variables.
  3. Solve the new 2x2 system using any method (substitution or elimination).
  4. Substitute the values of the two found variables back into any of the original equations to find the value of the third variable.

Examples

  • Given the system:
{x+2y+z=82x+yz=1xy+3z=8\begin{cases} x + 2y + z = 8 \\ 2x + y - z = 1 \\ x - y + 3z = 8 \end{cases}

From the first equation, we can isolate xx: x=82yzx = 8 - 2y - z. Substitute this into the other two equations to get a 2x2 system in terms of yy and zz.

  • Given the system:
{z=2x3yx+y+z=63x2y=7\begin{cases} z = 2x - 3y \\ x + y + z = 6 \\ 3x - 2y = 7 \end{cases}

Substitute z=2x3yz = 2x - 3y into the second equation: x+y+(2x3y)=6x + y + (2x - 3y) = 6, which simplifies to 3x2y=63x - 2y = 6. Now you have a 2x2 system with the equations 3x2y=63x - 2y = 6 and 3x2y=73x - 2y = 7, which indicates no solution.

Explanation

The substitution method systematically reduces a complex problem into a simpler one. By solving for one variable and substituting its expression into the other equations, you reduce a three-variable system to a familiar two-variable system. Once you solve the simpler system, you can work backwards to find the value of the initial variable. This strategy is particularly effective when one of the equations can be easily rearranged to isolate a variable.

Section 3

Gaussian reduction for three-variable systems

Property

Gaussian reduction is a systematic method for solving three-variable linear systems by using elimination to create a triangular form, then applying back-substitution.

Steps for Gaussian Reduction on a 3×33 \times 3 System:

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Coefficient Matching for Linear Expressions

Property

If two linear expressions are equal for all values of a variable, then their corresponding coefficients must be equal:

If ax+b=cx+dax + b = cx + d for all values of xx, then a=ca = c and b=db = d

Section 2

Solving 3x3 Systems by Substitution

Property

To solve a system of three equations with three variables using substitution, follow these steps:

  1. Solve one of the equations for one variable in terms of the other two.
  2. Substitute the resulting expression into the other two equations. This creates a new system of two equations with two variables.
  3. Solve the new 2x2 system using any method (substitution or elimination).
  4. Substitute the values of the two found variables back into any of the original equations to find the value of the third variable.

Examples

  • Given the system:
{x+2y+z=82x+yz=1xy+3z=8\begin{cases} x + 2y + z = 8 \\ 2x + y - z = 1 \\ x - y + 3z = 8 \end{cases}

From the first equation, we can isolate xx: x=82yzx = 8 - 2y - z. Substitute this into the other two equations to get a 2x2 system in terms of yy and zz.

  • Given the system:
{z=2x3yx+y+z=63x2y=7\begin{cases} z = 2x - 3y \\ x + y + z = 6 \\ 3x - 2y = 7 \end{cases}

Substitute z=2x3yz = 2x - 3y into the second equation: x+y+(2x3y)=6x + y + (2x - 3y) = 6, which simplifies to 3x2y=63x - 2y = 6. Now you have a 2x2 system with the equations 3x2y=63x - 2y = 6 and 3x2y=73x - 2y = 7, which indicates no solution.

Explanation

The substitution method systematically reduces a complex problem into a simpler one. By solving for one variable and substituting its expression into the other equations, you reduce a three-variable system to a familiar two-variable system. Once you solve the simpler system, you can work backwards to find the value of the initial variable. This strategy is particularly effective when one of the equations can be easily rearranged to isolate a variable.

Section 3

Gaussian reduction for three-variable systems

Property

Gaussian reduction is a systematic method for solving three-variable linear systems by using elimination to create a triangular form, then applying back-substitution.

Steps for Gaussian Reduction on a 3×33 \times 3 System: