Learn on PengiBig Ideas Math, Course 1Chapter 7: Equations and Inequalities

Lesson 6: Solving Inequalities Using Addition or Subtraction

In this Grade 6 lesson from Big Ideas Math Course 1, Chapter 7, students learn to solve one-variable inequalities using the Addition Property of Inequality and the Subtraction Property of Inequality. They practice isolating the variable by adding or subtracting the same number from both sides, then graphing the solution set on a number line using open or closed circles. Real-world contexts, such as voting age and manatee growth, help students write and interpret inequalities like x − 3 > 1 or 15 ≥ 6 + x.

Section 1

Addition and Subtraction Property of Inequality

Property

For any numbers aa, bb, and cc, if a<ba < b, then

a+c<b+cac<bca + c < b + c \qquad a - c < b - c

For any numbers aa, bb, and cc, if a>ba > b, then

a+c>b+cac>bca + c > b + c \qquad a - c > b - c

We can add or subtract the same quantity from both sides of an inequality and still keep the inequality.

Examples

  • To solve x+7<15x + 7 < 15, subtract 7 from both sides: x+77<157x + 7 - 7 < 15 - 7, which simplifies to x<8x < 8.
  • To solve y42y - 4 \geq -2, add 4 to both sides: y4+42+4y - 4 + 4 \geq -2 + 4, which simplifies to y2y \geq 2.
  • Given 12>z+512 > z + 5, subtract 5 from both sides: 125>z+5512 - 5 > z + 5 - 5, so 7>z7 > z, which means z<7z < 7.

Explanation

This property is just like it is for equations. You can add or subtract the same number on both sides of an inequality, and the relationship between the two sides stays the same. The inequality sign does not change.

Section 2

Solving One-Step Inequalities Using Addition and Subtraction

Property

To solve an inequality using addition or subtraction:

  1. We can add the same quantity to both sides of an inequality.
  2. We can subtract the same quantity from both sides of an inequality.
  3. The direction of the inequality sign remains unchanged when adding or subtracting.

Examples

Section 3

Application: Solving Word Problems with One-Step Inequalities

Property

To solve linear inequality applications, translate the word problem into a mathematical inequality, then solve using algebraic properties.
The key steps are: identify the variable, write the inequality from the given constraints, solve algebraically, and interpret the solution in context.

Examples

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Addition and Subtraction Property of Inequality

Property

For any numbers aa, bb, and cc, if a<ba < b, then

a+c<b+cac<bca + c < b + c \qquad a - c < b - c

For any numbers aa, bb, and cc, if a>ba > b, then

a+c>b+cac>bca + c > b + c \qquad a - c > b - c

We can add or subtract the same quantity from both sides of an inequality and still keep the inequality.

Examples

  • To solve x+7<15x + 7 < 15, subtract 7 from both sides: x+77<157x + 7 - 7 < 15 - 7, which simplifies to x<8x < 8.
  • To solve y42y - 4 \geq -2, add 4 to both sides: y4+42+4y - 4 + 4 \geq -2 + 4, which simplifies to y2y \geq 2.
  • Given 12>z+512 > z + 5, subtract 5 from both sides: 125>z+5512 - 5 > z + 5 - 5, so 7>z7 > z, which means z<7z < 7.

Explanation

This property is just like it is for equations. You can add or subtract the same number on both sides of an inequality, and the relationship between the two sides stays the same. The inequality sign does not change.

Section 2

Solving One-Step Inequalities Using Addition and Subtraction

Property

To solve an inequality using addition or subtraction:

  1. We can add the same quantity to both sides of an inequality.
  2. We can subtract the same quantity from both sides of an inequality.
  3. The direction of the inequality sign remains unchanged when adding or subtracting.

Examples

Section 3

Application: Solving Word Problems with One-Step Inequalities

Property

To solve linear inequality applications, translate the word problem into a mathematical inequality, then solve using algebraic properties.
The key steps are: identify the variable, write the inequality from the given constraints, solve algebraically, and interpret the solution in context.

Examples