Learn on PengiBig Ideas Math, Algebra 1Chapter 7: Polynomial Equations and Factoring

Lesson 8: Factoring Polynomials Completely

Property HOW TO: Factor polynomials. 1. Step 1. Is there a greatest common factor? Factor it out. 2. Step 2. Is the polynomial a binomial, trinomial, or are there more than three terms? If it is a binomial , check for a sum/difference of squares or cubes. If it is a trinomial , check if it is of the form $x^2 + bx + c$ or $ax^2 + bx + c$. If it has more than three terms , use the grouping method. 3. Step 3. Check. Is it factored completely? Do the factors multiply back to the original polynomial?

Section 1

General Factoring Strategy

Property

HOW TO: Factor polynomials.

  1. Step 1. Is there a greatest common factor? Factor it out.
  2. Step 2. Is the polynomial a binomial, trinomial, or are there more than three terms? If it is a binomial, check for a sum/difference of squares or cubes. If it is a trinomial, check if it is of the form x2+bx+cx^2 + bx + c or ax2+bx+cax^2 + bx + c. If it has more than three terms, use the grouping method.
  3. Step 3. Check. Is it factored completely? Do the factors multiply back to the original polynomial?

Examples

  • To factor 5x6+15x55x^6 + 15x^5, first find the GCF, which is 5x55x^5. Factoring it out gives 5x5(x+3)5x^5(x+3). The binomial (x+3)(x+3) is prime, so the factoring is complete.
  • To factor 4x28x604x^2 - 8x - 60, first factor out the GCF of 4, which gives 4(x22x15)4(x^2 - 2x - 15). Then factor the trinomial to get 4(x5)(x+3)4(x-5)(x+3).

Section 2

Factor Trinomials of the Form x²+bx+c

Property

To factor a trinomial of the form x2+bx+cx^2 + bx + c means to start with the product and end with the factors, (x+m)(x+n)(x+m)(x+n). To get the correct factors, we find two numbers mm and nn whose product is cc and sum is bb.

How to factor trinomials of the form x2+bx+cx^2 + bx + c:

  1. Write the factors as two binomials with first terms xx: (x)(x)(x \quad)(x \quad).
  2. Find two numbers mm and nn that multiply to cc (mn=cm \cdot n = c) and add to bb (m+n=bm+n = b).
  3. Use mm and nn as the last terms of the factors: (x+m)(x+n)(x+m)(x+n).
  4. Check by multiplying the factors.

Examples

  • To factor x2+9x+20x^2 + 9x + 20, we need two numbers that multiply to 20 and add to 9. The numbers are 4 and 5. So, the factors are (x+4)(x+5)(x+4)(x+5).
  • To factor a28a+15a^2 - 8a + 15, we need two numbers that multiply to 15 and add to -8. The numbers are -3 and -5. Thus, the factors are (a3)(a5)(a-3)(a-5).
  • To factor p2+3p10p^2 + 3p - 10, we need two numbers that multiply to -10 and add to 3. The numbers are 5 and -2. Therefore, the factors are (p+5)(p2)(p+5)(p-2).

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

General Factoring Strategy

Property

HOW TO: Factor polynomials.

  1. Step 1. Is there a greatest common factor? Factor it out.
  2. Step 2. Is the polynomial a binomial, trinomial, or are there more than three terms? If it is a binomial, check for a sum/difference of squares or cubes. If it is a trinomial, check if it is of the form x2+bx+cx^2 + bx + c or ax2+bx+cax^2 + bx + c. If it has more than three terms, use the grouping method.
  3. Step 3. Check. Is it factored completely? Do the factors multiply back to the original polynomial?

Examples

  • To factor 5x6+15x55x^6 + 15x^5, first find the GCF, which is 5x55x^5. Factoring it out gives 5x5(x+3)5x^5(x+3). The binomial (x+3)(x+3) is prime, so the factoring is complete.
  • To factor 4x28x604x^2 - 8x - 60, first factor out the GCF of 4, which gives 4(x22x15)4(x^2 - 2x - 15). Then factor the trinomial to get 4(x5)(x+3)4(x-5)(x+3).

Section 2

Factor Trinomials of the Form x²+bx+c

Property

To factor a trinomial of the form x2+bx+cx^2 + bx + c means to start with the product and end with the factors, (x+m)(x+n)(x+m)(x+n). To get the correct factors, we find two numbers mm and nn whose product is cc and sum is bb.

How to factor trinomials of the form x2+bx+cx^2 + bx + c:

  1. Write the factors as two binomials with first terms xx: (x)(x)(x \quad)(x \quad).
  2. Find two numbers mm and nn that multiply to cc (mn=cm \cdot n = c) and add to bb (m+n=bm+n = b).
  3. Use mm and nn as the last terms of the factors: (x+m)(x+n)(x+m)(x+n).
  4. Check by multiplying the factors.

Examples

  • To factor x2+9x+20x^2 + 9x + 20, we need two numbers that multiply to 20 and add to 9. The numbers are 4 and 5. So, the factors are (x+4)(x+5)(x+4)(x+5).
  • To factor a28a+15a^2 - 8a + 15, we need two numbers that multiply to 15 and add to -8. The numbers are -3 and -5. Thus, the factors are (a3)(a5)(a-3)(a-5).
  • To factor p2+3p10p^2 + 3p - 10, we need two numbers that multiply to -10 and add to 3. The numbers are 5 and -2. Therefore, the factors are (p+5)(p2)(p+5)(p-2).