To graph the inequality $y > -2x + 1$, you use the test point $(0, 0)$. Which conclusion is correct?

The result $0 > 1$ is false, so shade the half-plane that does not contain $(0, 0)$.

The result $0 > 1$ is false, so shade the half-plane that contains $(0, 0)$.

The result $0 < 1$ is true, so shade the half-plane that contains $(0, 0)$.

The point $(0, 0)$ is on the boundary line, so it cannot be used.

Why is the point $(0, 0)$ not a suitable test point for graphing the inequality $y < 3x$?

Because the point $(0, 0)$ lies on the boundary line $y = 3x$.

Because substituting $(0, 0)$ results in a false statement.

Because substituting $(0, 0)$ results in a true statement.

Because the inequality does not have a y-intercept term.

Shade the half-plane that contains the point $(0, 0)$.

Shade the half-plane that does not contain the point $(0, 0)$.

Choose a different test point because the result was positive.

Draw a solid line instead of a dashed line.