Which statement correctly demonstrates the transitivity property of divisors?

Since $6 \mid 12$ and $12 \mid 36$, then $6 \mid 36$.

Since $5 \mid 30$, then $30 = 5 \times 6$.

Since $3 \mid 15$ and $3 \mid 21$, then $3 \mid (15+21)$.

Since $10 = 2 \times 5$, then $2 \mid 10$ and $5 \mid 10$.

Given that $2 \mid 10$ and $10 \mid 50$, a student concludes that $2 \mid 50$. Is this conclusion a correct application of the transitivity property?

No, the conclusion is not valid.