Learn on PengiOpenstax Elementary Algebra 2EChapter 3: Math Models

Lesson 3.1: Use a Problem-Solving Strategy

In this lesson from OpenStax Elementary Algebra 2E, students learn how to apply a structured problem-solving strategy to translate word problems into algebraic equations and solve them. The strategy walks through steps including identifying what is being asked, assigning a variable, writing an equation, and checking the solution. The lesson also covers solving basic number problems using linear equations.

Section 1

πŸ“˜ Use a Problem-Solving Strategy

New Concept

Master a powerful 7-step strategy to confidently translate any word problem into a solvable equation. You'll learn to systematically break down problems, from simple number puzzles to real-world scenarios, and find the correct solution.

What’s next

You'll now walk through interactive examples using this 7-step method, followed by practice cards to test your new problem-solving skills.

Section 2

Use a Problem-Solving Strategy

Property

Use a Problem-Solving Strategy to Solve Word Problems.

  1. Read the problem. Make sure all the words and ideas are understood.
  2. Identify what we are looking for.
  3. Name what we are looking for. Choose a variable to represent that quantity.
  4. Translate into an equation. It may be helpful to restate the problem in one sentence with all the important information. Then, translate the English sentence into an algebraic equation.
  5. Solve the equation using good algebra techniques.
  6. Check the answer in the problem and make sure it makes sense.
  7. Answer the question with a complete sentence.

Examples

  • A shirt is on sale for 25 dollars, which is one-third of its original price. What was the original price? Let pp be the original price. The equation is 25=13p25 = \frac{1}{3}p. Solving for pp gives p=75p=75. The original price was 75 dollars.
  • A book club has 17 women. The number of women is two more than three times the number of men. How many men are in the club? Let mm be the number of men. The equation is 17=3m+217 = 3m + 2. Solving for mm gives m=5m=5. There are 5 men in the club.

Section 3

Solving Number Problems

Property

To solve number problems, translate key words from the sentence into mathematical operations. Restate the problem in a single sentence to clarify the relationship between the numbers. Common key words include:

  • Sum: Addition (+)
  • Difference: Subtraction (-)
  • Product/Times: Multiplication (β‹…)
  • Quotient: Division (Γ·)
  • Twice a number: 2n2n

Examples

  • The sum of twice a number and nine is 21. Find the number. Let nn be the number. The equation is 2n+9=212n + 9 = 21. Solving gives 2n=122n = 12, so n=6n=6. The number is 6.
  • The difference of a number and three is 15. Find the number. Let xx be the number. The equation is xβˆ’3=15x - 3 = 15. Solving gives x=18x=18. The number is 18.

Section 4

Problems with Two Unknowns

Property

When a problem involves two unknown quantities, name the first unknown with a variable (e.g., nn).
Then, read the problem to find the relationship between the two unknowns and write an expression for the second unknown using the same variable (e.g., n+5n+5 or 2nβˆ’102n-10).
Finally, form an equation that relates both unknowns and solve.

Examples

  • One number is ten more than another. Their sum is 52. Find the numbers. Let the first number be nn. The second is n+10n+10. The equation is n+(n+10)=52n + (n+10) = 52. This simplifies to 2n=422n=42, so n=21n=21. The numbers are 21 and 31.
  • The sum of two numbers is negative twenty. One number is six less than the other. Find the numbers. Let the first number be xx. The second is xβˆ’6x-6. The equation is x+(xβˆ’6)=βˆ’20x + (x-6) = -20. This simplifies to 2x=βˆ’142x = -14, so x=βˆ’7x=-7. The numbers are -7 and -13.

Section 5

Consecutive Integer Problems

Property

To solve problems involving consecutive integers, use a variable to represent the first integer and then write expressions for the following integers based on the pattern.

  • Consecutive Integers: n,n+1,n+2,…n, n+1, n+2, \dots
  • Consecutive Even Integers: n,n+2,n+4,…n, n+2, n+4, \dots (where nn is an even integer)
  • Consecutive Odd Integers: n,n+2,n+4,…n, n+2, n+4, \dots (where nn is an odd integer)

Examples

  • The sum of two consecutive integers is 51. Find the integers. Let the integers be nn and n+1n+1. The equation is n+(n+1)=51n+(n+1)=51. This gives 2n=502n=50, so n=25n=25. The integers are 25 and 26.
  • Find three consecutive even integers whose sum is 96. Let them be n,n+2,n+4n, n+2, n+4. The equation is n+(n+2)+(n+4)=96n+(n+2)+(n+4)=96. This gives 3n=903n=90, so n=30n=30. The integers are 30, 32, and 34.

Book overview

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Chapter 3: Math Models

  1. Lesson 1Current

    Lesson 3.1: Use a Problem-Solving Strategy

  2. Lesson 2

    Lesson 3.2: Solve Percent Applications

  3. Lesson 3

    Lesson 3.3: Solve Mixture Applications

  4. Lesson 4

    Lesson 3.4: Solve Geometry Applications: Triangles, Rectangles, and the Pythagorean Theorem

  5. Lesson 5

    Lesson 3.5: Solve Uniform Motion Applications

  6. Lesson 6

    Lesson 3.6: Solve Applications with Linear Inequalities

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Use a Problem-Solving Strategy

New Concept

Master a powerful 7-step strategy to confidently translate any word problem into a solvable equation. You'll learn to systematically break down problems, from simple number puzzles to real-world scenarios, and find the correct solution.

What’s next

You'll now walk through interactive examples using this 7-step method, followed by practice cards to test your new problem-solving skills.

Section 2

Use a Problem-Solving Strategy

Property

Use a Problem-Solving Strategy to Solve Word Problems.

  1. Read the problem. Make sure all the words and ideas are understood.
  2. Identify what we are looking for.
  3. Name what we are looking for. Choose a variable to represent that quantity.
  4. Translate into an equation. It may be helpful to restate the problem in one sentence with all the important information. Then, translate the English sentence into an algebraic equation.
  5. Solve the equation using good algebra techniques.
  6. Check the answer in the problem and make sure it makes sense.
  7. Answer the question with a complete sentence.

Examples

  • A shirt is on sale for 25 dollars, which is one-third of its original price. What was the original price? Let pp be the original price. The equation is 25=13p25 = \frac{1}{3}p. Solving for pp gives p=75p=75. The original price was 75 dollars.
  • A book club has 17 women. The number of women is two more than three times the number of men. How many men are in the club? Let mm be the number of men. The equation is 17=3m+217 = 3m + 2. Solving for mm gives m=5m=5. There are 5 men in the club.

Section 3

Solving Number Problems

Property

To solve number problems, translate key words from the sentence into mathematical operations. Restate the problem in a single sentence to clarify the relationship between the numbers. Common key words include:

  • Sum: Addition (+)
  • Difference: Subtraction (-)
  • Product/Times: Multiplication (β‹…)
  • Quotient: Division (Γ·)
  • Twice a number: 2n2n

Examples

  • The sum of twice a number and nine is 21. Find the number. Let nn be the number. The equation is 2n+9=212n + 9 = 21. Solving gives 2n=122n = 12, so n=6n=6. The number is 6.
  • The difference of a number and three is 15. Find the number. Let xx be the number. The equation is xβˆ’3=15x - 3 = 15. Solving gives x=18x=18. The number is 18.

Section 4

Problems with Two Unknowns

Property

When a problem involves two unknown quantities, name the first unknown with a variable (e.g., nn).
Then, read the problem to find the relationship between the two unknowns and write an expression for the second unknown using the same variable (e.g., n+5n+5 or 2nβˆ’102n-10).
Finally, form an equation that relates both unknowns and solve.

Examples

  • One number is ten more than another. Their sum is 52. Find the numbers. Let the first number be nn. The second is n+10n+10. The equation is n+(n+10)=52n + (n+10) = 52. This simplifies to 2n=422n=42, so n=21n=21. The numbers are 21 and 31.
  • The sum of two numbers is negative twenty. One number is six less than the other. Find the numbers. Let the first number be xx. The second is xβˆ’6x-6. The equation is x+(xβˆ’6)=βˆ’20x + (x-6) = -20. This simplifies to 2x=βˆ’142x = -14, so x=βˆ’7x=-7. The numbers are -7 and -13.

Section 5

Consecutive Integer Problems

Property

To solve problems involving consecutive integers, use a variable to represent the first integer and then write expressions for the following integers based on the pattern.

  • Consecutive Integers: n,n+1,n+2,…n, n+1, n+2, \dots
  • Consecutive Even Integers: n,n+2,n+4,…n, n+2, n+4, \dots (where nn is an even integer)
  • Consecutive Odd Integers: n,n+2,n+4,…n, n+2, n+4, \dots (where nn is an odd integer)

Examples

  • The sum of two consecutive integers is 51. Find the integers. Let the integers be nn and n+1n+1. The equation is n+(n+1)=51n+(n+1)=51. This gives 2n=502n=50, so n=25n=25. The integers are 25 and 26.
  • Find three consecutive even integers whose sum is 96. Let them be n,n+2,n+4n, n+2, n+4. The equation is n+(n+2)+(n+4)=96n+(n+2)+(n+4)=96. This gives 3n=903n=90, so n=30n=30. The integers are 30, 32, and 34.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Math Models

  1. Lesson 1Current

    Lesson 3.1: Use a Problem-Solving Strategy

  2. Lesson 2

    Lesson 3.2: Solve Percent Applications

  3. Lesson 3

    Lesson 3.3: Solve Mixture Applications

  4. Lesson 4

    Lesson 3.4: Solve Geometry Applications: Triangles, Rectangles, and the Pythagorean Theorem

  5. Lesson 5

    Lesson 3.5: Solve Uniform Motion Applications

  6. Lesson 6

    Lesson 3.6: Solve Applications with Linear Inequalities