Learn on PengiOpenstax Intermediate Algebra 2EChapter 3: Graphs and Functions

Lesson 3.4: Graph Linear Inequalities in Two Variables

New Concept We're expanding from single variable inequalities to those with two variables, like $Ax + By C$. This lesson teaches you how to graph these inequalities, where the solution isn't just a line, but a whole region on the coordinate plane.

Section 1

πŸ“˜ Graph Linear Inequalities in Two Variables

New Concept

We're expanding from single-variable inequalities to those with two variables, like Ax+By>CAx + By > C. This lesson teaches you how to graph these inequalities, where the solution isn't just a line, but a whole region on the coordinate plane.

What’s next

Next up, you'll tackle interactive graphing examples, practice identifying solution regions, and solve real-world problems. Let's start graphing!

Section 2

Linear Inequality

Property

A linear inequality is an inequality that can be written in one of the following forms:

Ax+By>CAx+Byβ‰₯CAx+By<CAx+By≀CAx + By > C \quad Ax + By \geq C \quad Ax + By < C \quad Ax + By \leq C

Where AA and BB are not both zero.

Examples

  • An ordered pair (x,y)(x, y) is a solution if it makes the inequality true. For y>x+4y > x + 4, the point (1,6)(1, 6) is a solution because 6>1+46 > 1 + 4 is true.
  • For the same inequality y>x+4y > x + 4, the point (2,6)(2, 6) is not a solution because 6>2+46 > 2 + 4 simplifies to 6>66 > 6, which is false.

Section 3

Solution to a Linear Inequality

Property

An ordered pair (x,y)(x, y) is a solution to a linear inequality if the inequality is true when we substitute the values of xx and yy.

Examples

  • Is (2,5)(2, 5) a solution to y<2x+3y < 2x + 3? Substitute the values: 5<?2(2)+35 \stackrel{?}{<} 2(2) + 3. This simplifies to 5<75 < 7, which is true. So, (2,5)(2, 5) is a solution.
  • Is (βˆ’1,4)(-1, 4) a solution to y<2x+3y < 2x + 3? Substitute the values: 4<?2(βˆ’1)+34 \stackrel{?}{<} 2(-1) + 3. This simplifies to 4<14 < 1, which is false. So, (βˆ’1,4)(-1, 4) is not a solution.

Section 4

The Boundary Line

Property

The line with equation Ax+By=CAx + By = C is the boundary line that separates the region where Ax+By>CAx + By > C from the region where Ax+By<CAx + By < C.

Ax+By<CAx+By≀CAx+By>CAx+Byβ‰₯CBoundaryΒ lineΒ isΒ Ax+By=CBoundaryΒ lineΒ isΒ Ax+By=CBoundaryΒ lineΒ isΒ notΒ includedΒ inΒ solution.BoundaryΒ lineΒ isΒ includedΒ inΒ solution.BoundaryΒ lineΒ isΒ dashed.BoundaryΒ lineΒ isΒ solid.\begin{array}{ll} Ax + By < C & Ax + By \leq C \\ Ax + By > C & Ax + By \geq C \\ \text{Boundary line is } Ax + By = C & \text{Boundary line is } Ax + By = C \\ \text{Boundary line is not included in solution.} & \text{Boundary line is included in solution.} \\ \text{Boundary line is dashed.} & \text{Boundary line is solid.} \end{array}

Examples

  • For the inequality y≀3xβˆ’1y \leq 3x - 1, the boundary line is y=3xβˆ’1y = 3x - 1. Since the inequality is 'less than or equal to' (≀\leq), the line is solid.
  • For the inequality x+5y>10x + 5y > 10, the boundary line is x+5y=10x + 5y = 10. Since the inequality is 'greater than' (>>), the line is dashed.

Section 5

Graphing Linear Inequalities

Property

How to graph a linear inequality in two variables.

  • Step 1. Identify and graph the boundary line. If the inequality is ≀\leq or β‰₯\geq, the boundary line is solid. If the inequality is << or >>, the boundary line is dashed.
  • Step 2. Test a point that is not on the boundary line. Is it a solution of the inequality?
  • Step 3. Shade in one side of the boundary line. If the test point is a solution, shade in the side that includes the point. If the test point is not a solution, shade in the opposite side.

Examples

  • To graph yβ‰₯2xβˆ’3y \geq 2x - 3: Draw the solid line y=2xβˆ’3y = 2x - 3. Test (0,0)(0,0): 0β‰₯2(0)βˆ’30 \geq 2(0) - 3 is 0β‰₯βˆ’30 \geq -3, which is true. Shade the side containing (0,0)(0,0).
  • To graph xβˆ’3y<6x - 3y < 6: Draw the dashed line xβˆ’3y=6x - 3y = 6. Test (0,0)(0,0): 0βˆ’3(0)<60 - 3(0) < 6 is 0<60 < 6, which is true. Shade the side containing (0,0)(0,0).

Book overview

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Continue this chapter

Chapter 3: Graphs and Functions

  1. Lesson 1

    Lesson 3.1: Graph Linear Equations in Two Variables

  2. Lesson 2

    Lesson 3.2: Slope of a Line

  3. Lesson 3

    Lesson 3.3: Find the Equation of a Line

  4. Lesson 4Current

    Lesson 3.4: Graph Linear Inequalities in Two Variables

  5. Lesson 5

    Lesson 3.5: Relations and Functions

  6. Lesson 6

    Lesson 3.6: Graphs of Functions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Graph Linear Inequalities in Two Variables

New Concept

We're expanding from single-variable inequalities to those with two variables, like Ax+By>CAx + By > C. This lesson teaches you how to graph these inequalities, where the solution isn't just a line, but a whole region on the coordinate plane.

What’s next

Next up, you'll tackle interactive graphing examples, practice identifying solution regions, and solve real-world problems. Let's start graphing!

Section 2

Linear Inequality

Property

A linear inequality is an inequality that can be written in one of the following forms:

Ax+By>CAx+Byβ‰₯CAx+By<CAx+By≀CAx + By > C \quad Ax + By \geq C \quad Ax + By < C \quad Ax + By \leq C

Where AA and BB are not both zero.

Examples

  • An ordered pair (x,y)(x, y) is a solution if it makes the inequality true. For y>x+4y > x + 4, the point (1,6)(1, 6) is a solution because 6>1+46 > 1 + 4 is true.
  • For the same inequality y>x+4y > x + 4, the point (2,6)(2, 6) is not a solution because 6>2+46 > 2 + 4 simplifies to 6>66 > 6, which is false.

Section 3

Solution to a Linear Inequality

Property

An ordered pair (x,y)(x, y) is a solution to a linear inequality if the inequality is true when we substitute the values of xx and yy.

Examples

  • Is (2,5)(2, 5) a solution to y<2x+3y < 2x + 3? Substitute the values: 5<?2(2)+35 \stackrel{?}{<} 2(2) + 3. This simplifies to 5<75 < 7, which is true. So, (2,5)(2, 5) is a solution.
  • Is (βˆ’1,4)(-1, 4) a solution to y<2x+3y < 2x + 3? Substitute the values: 4<?2(βˆ’1)+34 \stackrel{?}{<} 2(-1) + 3. This simplifies to 4<14 < 1, which is false. So, (βˆ’1,4)(-1, 4) is not a solution.

Section 4

The Boundary Line

Property

The line with equation Ax+By=CAx + By = C is the boundary line that separates the region where Ax+By>CAx + By > C from the region where Ax+By<CAx + By < C.

Ax+By<CAx+By≀CAx+By>CAx+Byβ‰₯CBoundaryΒ lineΒ isΒ Ax+By=CBoundaryΒ lineΒ isΒ Ax+By=CBoundaryΒ lineΒ isΒ notΒ includedΒ inΒ solution.BoundaryΒ lineΒ isΒ includedΒ inΒ solution.BoundaryΒ lineΒ isΒ dashed.BoundaryΒ lineΒ isΒ solid.\begin{array}{ll} Ax + By < C & Ax + By \leq C \\ Ax + By > C & Ax + By \geq C \\ \text{Boundary line is } Ax + By = C & \text{Boundary line is } Ax + By = C \\ \text{Boundary line is not included in solution.} & \text{Boundary line is included in solution.} \\ \text{Boundary line is dashed.} & \text{Boundary line is solid.} \end{array}

Examples

  • For the inequality y≀3xβˆ’1y \leq 3x - 1, the boundary line is y=3xβˆ’1y = 3x - 1. Since the inequality is 'less than or equal to' (≀\leq), the line is solid.
  • For the inequality x+5y>10x + 5y > 10, the boundary line is x+5y=10x + 5y = 10. Since the inequality is 'greater than' (>>), the line is dashed.

Section 5

Graphing Linear Inequalities

Property

How to graph a linear inequality in two variables.

  • Step 1. Identify and graph the boundary line. If the inequality is ≀\leq or β‰₯\geq, the boundary line is solid. If the inequality is << or >>, the boundary line is dashed.
  • Step 2. Test a point that is not on the boundary line. Is it a solution of the inequality?
  • Step 3. Shade in one side of the boundary line. If the test point is a solution, shade in the side that includes the point. If the test point is not a solution, shade in the opposite side.

Examples

  • To graph yβ‰₯2xβˆ’3y \geq 2x - 3: Draw the solid line y=2xβˆ’3y = 2x - 3. Test (0,0)(0,0): 0β‰₯2(0)βˆ’30 \geq 2(0) - 3 is 0β‰₯βˆ’30 \geq -3, which is true. Shade the side containing (0,0)(0,0).
  • To graph xβˆ’3y<6x - 3y < 6: Draw the dashed line xβˆ’3y=6x - 3y = 6. Test (0,0)(0,0): 0βˆ’3(0)<60 - 3(0) < 6 is 0<60 < 6, which is true. Shade the side containing (0,0)(0,0).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Graphs and Functions

  1. Lesson 1

    Lesson 3.1: Graph Linear Equations in Two Variables

  2. Lesson 2

    Lesson 3.2: Slope of a Line

  3. Lesson 3

    Lesson 3.3: Find the Equation of a Line

  4. Lesson 4Current

    Lesson 3.4: Graph Linear Inequalities in Two Variables

  5. Lesson 5

    Lesson 3.5: Relations and Functions

  6. Lesson 6

    Lesson 3.6: Graphs of Functions