Learn on PengiBig Ideas Math, Advanced 2Chapter 8: Volume and Similar Solids

Section 8.3: Volumes of Spheres

In this Grade 7 lesson from Big Ideas Math Advanced 2, students learn how to calculate the volume of a sphere using the formula V = (4/3)πr³, derived by comparing a sphere's volume to that of a cylinder and through a pyramids approach. Students practice applying the formula to find both the volume and the radius of spheres, then extend their skills to composite solids involving hemispheres. The lesson builds on prior work with cylinders and pyramids in Chapter 8's exploration of volume and similar solids.

Section 1

Sphere Volume from Cylinder Relationship

Property

The volume of a sphere is 23\frac{2}{3} times the volume of a cylinder that has the same diameter as the sphere and height equal to the diameter:

Vsphere=23×Vcylinder=23×πr2hV_{sphere} = \frac{2}{3} \times V_{cylinder} = \frac{2}{3} \times \pi r^2 h

When h=2rh = 2r (diameter), this becomes:

Vsphere=23×πr2(2r)=43πr3V_{sphere} = \frac{2}{3} \times \pi r^2 (2r) = \frac{4}{3}\pi r^3

Section 2

Volume of a Sphere

Property

The volume of a sphere is given by

Volume=43×πr3\text{Volume} = \dfrac{4}{3} \times \pi r^3

where rr is the radius of the sphere. Recall that r3r^3, which we read as 'rr cubed,' means r×r×rr \times r \times r.

Examples

  • A gumball has a radius of 1 centimeter. Its volume is V=43π(1)3=43π4.19V = \frac{4}{3} \pi (1)^3 = \frac{4}{3}\pi \approx 4.19 cubic centimeters.
  • A soccer ball has a diameter of 22 cm, so its radius is 11 cm. Its volume is V=43π(11)3=43π(1331)5575.28V = \frac{4}{3} \pi (11)^3 = \frac{4}{3} \pi (1331) \approx 5575.28 cubic centimeters.
  • A spherical ornament has a volume of 36π36\pi cubic inches. To find its radius, solve 36π=43πr336\pi = \frac{4}{3}\pi r^3, which simplifies to 27=r327 = r^3, so the radius is r=273=3r = \sqrt[3]{27} = 3 inches.

Explanation

Volume measures the space inside a 3D shape, like a ball or a planet. For a sphere, you cube the radius (multiply it by itself three times), then multiply by pi (π\pi), and finally multiply by the fraction 43\frac{4}{3}.

Section 3

Deriving Sphere Volume Using Pyramid Method

Property

The volume of a sphere can be derived by dividing it into many small pyramids with vertices at the center:

V=13×Surface Area×r=13×4πr2×r=43πr3V = \frac{1}{3} \times \text{Surface Area} \times r = \frac{1}{3} \times 4\pi r^2 \times r = \frac{4}{3}\pi r^3

Examples

Book overview

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Chapter 8: Volume and Similar Solids

  1. Lesson 1

    Section 8.1: Volumes of Cylinders

  2. Lesson 2

    Section 8.2: Volumes of Cones

  3. Lesson 3Current

    Section 8.3: Volumes of Spheres

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Sphere Volume from Cylinder Relationship

Property

The volume of a sphere is 23\frac{2}{3} times the volume of a cylinder that has the same diameter as the sphere and height equal to the diameter:

Vsphere=23×Vcylinder=23×πr2hV_{sphere} = \frac{2}{3} \times V_{cylinder} = \frac{2}{3} \times \pi r^2 h

When h=2rh = 2r (diameter), this becomes:

Vsphere=23×πr2(2r)=43πr3V_{sphere} = \frac{2}{3} \times \pi r^2 (2r) = \frac{4}{3}\pi r^3

Section 2

Volume of a Sphere

Property

The volume of a sphere is given by

Volume=43×πr3\text{Volume} = \dfrac{4}{3} \times \pi r^3

where rr is the radius of the sphere. Recall that r3r^3, which we read as 'rr cubed,' means r×r×rr \times r \times r.

Examples

  • A gumball has a radius of 1 centimeter. Its volume is V=43π(1)3=43π4.19V = \frac{4}{3} \pi (1)^3 = \frac{4}{3}\pi \approx 4.19 cubic centimeters.
  • A soccer ball has a diameter of 22 cm, so its radius is 11 cm. Its volume is V=43π(11)3=43π(1331)5575.28V = \frac{4}{3} \pi (11)^3 = \frac{4}{3} \pi (1331) \approx 5575.28 cubic centimeters.
  • A spherical ornament has a volume of 36π36\pi cubic inches. To find its radius, solve 36π=43πr336\pi = \frac{4}{3}\pi r^3, which simplifies to 27=r327 = r^3, so the radius is r=273=3r = \sqrt[3]{27} = 3 inches.

Explanation

Volume measures the space inside a 3D shape, like a ball or a planet. For a sphere, you cube the radius (multiply it by itself three times), then multiply by pi (π\pi), and finally multiply by the fraction 43\frac{4}{3}.

Section 3

Deriving Sphere Volume Using Pyramid Method

Property

The volume of a sphere can be derived by dividing it into many small pyramids with vertices at the center:

V=13×Surface Area×r=13×4πr2×r=43πr3V = \frac{1}{3} \times \text{Surface Area} \times r = \frac{1}{3} \times 4\pi r^2 \times r = \frac{4}{3}\pi r^3

Examples

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Volume and Similar Solids

  1. Lesson 1

    Section 8.1: Volumes of Cylinders

  2. Lesson 2

    Section 8.2: Volumes of Cones

  3. Lesson 3Current

    Section 8.3: Volumes of Spheres