Learn on PengiSaxon Math, Intermediate 4Chapter 7: Lessons 61–70, Investigation 7

Lesson 67: Multiplying by Multiples of 10

In this Grade 4 lesson from Saxon Math Intermediate 4, students learn how to multiply whole numbers and decimal numbers by multiples of 10, using strategies such as decomposing the multiplier (e.g., rewriting 30 as 3 × 10) and the "hanging zero" method. The lesson covers multiplying two- and three-digit numbers as well as money amounts by multiples like 10, 20, 30, and 50. Practice problems include real-world contexts such as calculating total costs and counting spelling words checked by a teacher.

Section 1

📘 Multiplying by Multiples of 10

New Concept

To multiply a whole number or a decimal number by a multiple of 10, we may write the multiple of 10 so that the zero 'hangs out' to the right.

What’s next

Next, you’ll apply this 'hang out' method to multiply whole numbers, decimals, and solve word problems.

Section 2

Multiplying by multiples of 10

To multiply a number by a multiple of 10, like 20, you can first break the multiple into its factors. For example, since 20 is equal to 2×102 \times 10, you can solve 34×2034 \times 20 by calculating 34×2×1034 \times 2 \times 10. This turns one big multiplication problem into two smaller, more manageable steps.

Example 1: Solve 25×3025 \times 30 by factoring. First, rewrite 30 as 3×103 \times 10. The problem becomes 25×3×1025 \times 3 \times 10. Then, calculate 25×3=7525 \times 3 = 75. Finally, multiply by 10 to get 75×10=75075 \times 10 = 750. Example 2: To solve 12×3012 \times 30, we can express it as 12×3×1012 \times 3 \times 10. First, 12×3=3612 \times 3 = 36. Then, 36×10=36036 \times 10 = 360.

Think of this as a strategic detour! Instead of tackling a big number like 40 all at once, you can multiply by 4 first, which is much easier, and then multiply that result by 10. It’s like breaking a long journey into two short, easy trips, ensuring you arrive at the correct answer without getting lost in large numbers.

Section 3

Hanging out the zero

When multiplying by a multiple of 10 vertically, you can write the problem so the zero 'hangs out' to the right. First, bring the hanging zero straight down into the answer. Then, simply multiply the remaining numbers as you normally would. This is a quick and organized shortcut for these types of problems.

Example 1: To calculate 34×2034 \times 20, write the 20 below the 34 with the 0 hanging out. Drop the 0 into the answer. Then, multiply 34×2=6834 \times 2 = 68. The final answer is 680680. Example 2: For 45×5045 \times 50, let the 0 hang out and drop it down. Then, calculate 45×5=22545 \times 5 = 225. Your result is 22502250. Example 3: Solving 409×70409 \times 70, you drop the 0 and then multiply 409×7=2863409 \times 7 = 2863. The final answer is 2863028630.

Give that zero a break and let it hang out! This cool trick cleans up your workspace by letting you drop the zero straight down into the answer line. After that, you can forget about it and focus on the simpler multiplication problem that’s left over. It’s a fantastic way to keep your calculations neat and avoid simple mistakes.

Section 4

Multiplying decimals by multiples of 10

To multiply a decimal number by a multiple of 10, use the 'hanging zero' method. After you get a product, you must place the decimal point correctly. Count the number of digits after the decimal point in the original decimal number, and make sure your final answer has the same number of decimal places.

Example 1: To find the total cost of 20 items at 1.43 dollars each, multiply 1.43×201.43 \times 20. Let the zero hang out and drop down. Then, 143×2=286143 \times 2 = 286. Since 1.43 has two decimal places, the answer is 28.60 dollars. Example 2: For 1.64×301.64 \times 30, drop the 0 and multiply 164×3=492164 \times 3 = 492. Since 1.64 has two decimal places, the answer is 49.20 dollars.

This is the same 'hanging zero' party, but with a special guest: the decimal point! Do your multiplication just as you learned, then stop and count the decimal places in the number you started with. Your final answer must have the exact same number of places after the decimal. It ensures your dollars and cents are always on point!

Book overview

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Chapter 7: Lessons 61–70, Investigation 7

  1. Lesson 1

    Lesson 61: Remaining Fraction, Two-Step Equations

  2. Lesson 2

    Lesson 62: Multiplying Three or More Factors, Exponents

  3. Lesson 3

    Lesson 63: Polygons

  4. Lesson 4

    Lesson 64: Division with Two-Digit Answers, Part 1

  5. Lesson 5

    Lesson 65: Division with Two-Digit Answers, Part 2

  6. Lesson 6

    Lesson 66: Similar and Congruent Figures

  7. Lesson 7Current

    Lesson 67: Multiplying by Multiples of 10

  8. Lesson 8

    Lesson 68: Division with Two-Digit Answers and a Remainder

  9. Lesson 9

    Lesson 69: Millimeters

  10. Lesson 10

    Lesson 70: Word Problems About a Fraction of a Group

  11. Lesson 11

    Investigation 7: Collecting Data with Surveys, Activity Class Survey

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Multiplying by Multiples of 10

New Concept

To multiply a whole number or a decimal number by a multiple of 10, we may write the multiple of 10 so that the zero 'hangs out' to the right.

What’s next

Next, you’ll apply this 'hang out' method to multiply whole numbers, decimals, and solve word problems.

Section 2

Multiplying by multiples of 10

To multiply a number by a multiple of 10, like 20, you can first break the multiple into its factors. For example, since 20 is equal to 2×102 \times 10, you can solve 34×2034 \times 20 by calculating 34×2×1034 \times 2 \times 10. This turns one big multiplication problem into two smaller, more manageable steps.

Example 1: Solve 25×3025 \times 30 by factoring. First, rewrite 30 as 3×103 \times 10. The problem becomes 25×3×1025 \times 3 \times 10. Then, calculate 25×3=7525 \times 3 = 75. Finally, multiply by 10 to get 75×10=75075 \times 10 = 750. Example 2: To solve 12×3012 \times 30, we can express it as 12×3×1012 \times 3 \times 10. First, 12×3=3612 \times 3 = 36. Then, 36×10=36036 \times 10 = 360.

Think of this as a strategic detour! Instead of tackling a big number like 40 all at once, you can multiply by 4 first, which is much easier, and then multiply that result by 10. It’s like breaking a long journey into two short, easy trips, ensuring you arrive at the correct answer without getting lost in large numbers.

Section 3

Hanging out the zero

When multiplying by a multiple of 10 vertically, you can write the problem so the zero 'hangs out' to the right. First, bring the hanging zero straight down into the answer. Then, simply multiply the remaining numbers as you normally would. This is a quick and organized shortcut for these types of problems.

Example 1: To calculate 34×2034 \times 20, write the 20 below the 34 with the 0 hanging out. Drop the 0 into the answer. Then, multiply 34×2=6834 \times 2 = 68. The final answer is 680680. Example 2: For 45×5045 \times 50, let the 0 hang out and drop it down. Then, calculate 45×5=22545 \times 5 = 225. Your result is 22502250. Example 3: Solving 409×70409 \times 70, you drop the 0 and then multiply 409×7=2863409 \times 7 = 2863. The final answer is 2863028630.

Give that zero a break and let it hang out! This cool trick cleans up your workspace by letting you drop the zero straight down into the answer line. After that, you can forget about it and focus on the simpler multiplication problem that’s left over. It’s a fantastic way to keep your calculations neat and avoid simple mistakes.

Section 4

Multiplying decimals by multiples of 10

To multiply a decimal number by a multiple of 10, use the 'hanging zero' method. After you get a product, you must place the decimal point correctly. Count the number of digits after the decimal point in the original decimal number, and make sure your final answer has the same number of decimal places.

Example 1: To find the total cost of 20 items at 1.43 dollars each, multiply 1.43×201.43 \times 20. Let the zero hang out and drop down. Then, 143×2=286143 \times 2 = 286. Since 1.43 has two decimal places, the answer is 28.60 dollars. Example 2: For 1.64×301.64 \times 30, drop the 0 and multiply 164×3=492164 \times 3 = 492. Since 1.64 has two decimal places, the answer is 49.20 dollars.

This is the same 'hanging zero' party, but with a special guest: the decimal point! Do your multiplication just as you learned, then stop and count the decimal places in the number you started with. Your final answer must have the exact same number of places after the decimal. It ensures your dollars and cents are always on point!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Lessons 61–70, Investigation 7

  1. Lesson 1

    Lesson 61: Remaining Fraction, Two-Step Equations

  2. Lesson 2

    Lesson 62: Multiplying Three or More Factors, Exponents

  3. Lesson 3

    Lesson 63: Polygons

  4. Lesson 4

    Lesson 64: Division with Two-Digit Answers, Part 1

  5. Lesson 5

    Lesson 65: Division with Two-Digit Answers, Part 2

  6. Lesson 6

    Lesson 66: Similar and Congruent Figures

  7. Lesson 7Current

    Lesson 67: Multiplying by Multiples of 10

  8. Lesson 8

    Lesson 68: Division with Two-Digit Answers and a Remainder

  9. Lesson 9

    Lesson 69: Millimeters

  10. Lesson 10

    Lesson 70: Word Problems About a Fraction of a Group

  11. Lesson 11

    Investigation 7: Collecting Data with Surveys, Activity Class Survey