Learn on PengiBig Ideas Math, Algebra 2Chapter 4: Polynomial Functions

Lesson 9: Modeling with Polynomial Functions

In this Grade 8 lesson from Big Ideas Math Algebra 2, Chapter 4, students learn how to model real-life data using polynomial functions by writing cubic functions from given points and applying finite differences to determine the degree of a polynomial that fits equally-spaced data. Students use x-intercepts and known coordinate points to construct factored-form polynomial equations, then verify polynomial degree by analyzing whether first, second, or higher-order differences of y-values are constant and nonzero. The lesson also covers using graphing calculator regression tools to find best-fit polynomial models and evaluate their validity for real-world applications such as baseball distance data.

Section 1

Writing Cubic Functions in Factored Form

Property

A cubic function with three x-intercepts r1r_1, r2r_2, and r3r_3 can be written in factored form as:

f(x)=a(xr1)(xr2)(xr3)f(x) = a(x - r_1)(x - r_2)(x - r_3)

where aa is a nonzero constant that determines the vertical stretch and orientation.

Examples

Section 2

Using Finite Differences to Determine Polynomial Degree

Property

For equally spaced xx-values, if the nnth finite differences are constant and nonzero, then the data can be modeled by a polynomial of degree nn. The finite differences are calculated by repeatedly finding differences of consecutive yy-values: Δy=yi+1yi\Delta y = y_{i+1} - y_i.

Examples

Section 3

Fitting a parabola to data

Property

The simplest way to fit a parabola to a set of data points is to pick three of the points and find the equation of the parabola that passes through those three points. This creates a quadratic model, y=ax2+bx+cy = ax^2 + bx + c, for the relationship shown in the data.

Examples

  • A ball's height is measured at three times: (1,21)(1, 21), (2,24)(2, 24), and (3,21)(3, 21). Fitting a parabola gives the model h=3t2+12t+12h = -3t^2 + 12t + 12, which describes the ball's trajectory.
  • Data for driving cost at different speeds are (50,6.20)(50, 6.20), (60,7.80)(60, 7.80), and (70,10.60)(70, 10.60). We can fit a parabola C=av2+bv+cC = av^2 + bv + c to model how cost changes with speed, finding C=0.006v20.5v+16.2C = 0.006v^2 - 0.5v + 16.2.

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Chapter 4: Polynomial Functions

  1. Lesson 1

    Lesson 1: Graphing Polynomial Functions

  2. Lesson 2

    Lesson 2: Adding, Subtracting, and Multiplying Polynomials

  3. Lesson 3

    Lesson 4: Factoring Polynomials

  4. Lesson 4

    Lesson 5: Solving Polynomial Equations

  5. Lesson 5

    Lesson 6: The Fundamental Theorem of Algebra

  6. Lesson 6

    Lesson 7: Transformations of Polynomial Functions

  7. Lesson 7

    Lesson 8: Analyzing Graphs of Polynomial Functions

  8. Lesson 8Current

    Lesson 9: Modeling with Polynomial Functions

Lesson overview

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Section 1

Writing Cubic Functions in Factored Form

Property

A cubic function with three x-intercepts r1r_1, r2r_2, and r3r_3 can be written in factored form as:

f(x)=a(xr1)(xr2)(xr3)f(x) = a(x - r_1)(x - r_2)(x - r_3)

where aa is a nonzero constant that determines the vertical stretch and orientation.

Examples

Section 2

Using Finite Differences to Determine Polynomial Degree

Property

For equally spaced xx-values, if the nnth finite differences are constant and nonzero, then the data can be modeled by a polynomial of degree nn. The finite differences are calculated by repeatedly finding differences of consecutive yy-values: Δy=yi+1yi\Delta y = y_{i+1} - y_i.

Examples

Section 3

Fitting a parabola to data

Property

The simplest way to fit a parabola to a set of data points is to pick three of the points and find the equation of the parabola that passes through those three points. This creates a quadratic model, y=ax2+bx+cy = ax^2 + bx + c, for the relationship shown in the data.

Examples

  • A ball's height is measured at three times: (1,21)(1, 21), (2,24)(2, 24), and (3,21)(3, 21). Fitting a parabola gives the model h=3t2+12t+12h = -3t^2 + 12t + 12, which describes the ball's trajectory.
  • Data for driving cost at different speeds are (50,6.20)(50, 6.20), (60,7.80)(60, 7.80), and (70,10.60)(70, 10.60). We can fit a parabola C=av2+bv+cC = av^2 + bv + c to model how cost changes with speed, finding C=0.006v20.5v+16.2C = 0.006v^2 - 0.5v + 16.2.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Polynomial Functions

  1. Lesson 1

    Lesson 1: Graphing Polynomial Functions

  2. Lesson 2

    Lesson 2: Adding, Subtracting, and Multiplying Polynomials

  3. Lesson 3

    Lesson 4: Factoring Polynomials

  4. Lesson 4

    Lesson 5: Solving Polynomial Equations

  5. Lesson 5

    Lesson 6: The Fundamental Theorem of Algebra

  6. Lesson 6

    Lesson 7: Transformations of Polynomial Functions

  7. Lesson 7

    Lesson 8: Analyzing Graphs of Polynomial Functions

  8. Lesson 8Current

    Lesson 9: Modeling with Polynomial Functions