Learn on PengiSaxon Math, Course 2Chapter 8: Lessons 71-80, Investigation 8

Lesson 75: Area of a Complex Figure, Area of a Trapezoid

In this Grade 7 Saxon Math Course 2 lesson, students learn to find the area of complex figures by dividing them into rectangles and triangles, then adding or subtracting the component areas. The lesson also introduces the trapezoid area formula A = ½(b₁ + b₂)h, explaining how multiplying the average of the two parallel bases by the height gives the correct area.

Section 1

📘 Area of a Complex Figure, Area of a Trapezoid

New Concept

To find the area of a trapezoid, we use the average of its parallel bases and its height. The textbook provides two equivalent formulas for this.

Area of a Trapezoid

extArea=extaverageofthebases×extheight ext{Area} = ext{average of the bases} \times ext{height}
A=12(b1+b2)h A = \frac{1}{2}(b_1 + b_2)h

What’s next

Next, you'll apply these formulas in worked examples involving both trapezoids and more complex figures. We will also practice estimation strategies for quick calculations.

Section 2

Area of a complex figure

Property

To find the area of a complex figure, divide it into simpler shapes (like rectangles and triangles) and add their individual areas. Alternatively, enclose the figure in a larger rectangle and subtract the areas of the parts that are not included.

Examples

  • Method 1 (Addition): Divide the figure into a 5×85 \times 8 rectangle and a triangle with base 4 and height 8. Area = (5×8)+12(4×8)=40+16=56 units2(5 \times 8) + \frac{1}{2}(4 \times 8) = 40 + 16 = 56 \text{ units}^2.
  • Method 2 (Subtraction): Enclose the figure in a 12×1212 \times 12 square and subtract a 5×85 \times 8 triangle. Area = (12×12)12(5×8)=14420=124 units2(12 \times 12) - \frac{1}{2}(5 \times 8) = 144 - 20 = 124 \text{ units}^2.

Explanation

To find the area of a funky-shaped figure, slice it up into familiar shapes like rectangles and triangles. Calculate the area of each piece, then add them all up for the grand total! Alternatively, you can frame the figure inside a big rectangle and subtract the areas of the leftover bits you don't need.

Section 3

Area of a trapezoid

Property

To find the area of a trapezoid, multiply the average of the bases by the height. The formula is:

A=12(b1+b2)hA = \frac{1}{2}(b_1 + b_2)h

Examples

  • A trapezoid has bases b1=8b_1 = 8 cm and b2=12b_2 = 12 cm, and height h=5h = 5 cm. Area = 12(8+12)×5=12(20)×5=50 cm2\frac{1}{2}(8 + 12) \times 5 = \frac{1}{2}(20) \times 5 = 50 \text{ cm}^2.
  • Find the area of a trapezoid with bases of 11 m and 15 m and a height of 8 m. Area = 12(11+15)×8=12(26)×8=104 m2\frac{1}{2}(11 + 15) \times 8 = \frac{1}{2}(26) \times 8 = 104 \text{ m}^2.

Explanation

A trapezoid has two different parallel sides, so which one do we use? Neither! The trick is to find the average of the two bases, then multiply that average by the height. This clever shortcut transforms the trapezoid into a simple rectangle with the same area, making the calculation super straightforward and avoiding any guesswork.

Section 4

Estimate Area

Property

To estimate the area of a figure, first round its dimensions (like base and height) to the nearest convenient numbers. Then, use these rounded numbers to perform the area calculation for a quick approximation.

Examples

  • Estimate the area of a trapezoid with bases 4.94.9 ft and 8.28.2 ft and height 5.85.8 ft. Round to bases 5 and 8, height 6. Area 12(5+8)×6=39 ft2\approx \frac{1}{2}(5 + 8) \times 6 = 39 \text{ ft}^2.
  • Estimate the area of a book cover with parallel sides 3783 \frac{7}{8} in. and 6186 \frac{1}{8} in. and a height of 4 in. Round bases to 4 and 6. Area 12(4+6)×4=20 in2\approx \frac{1}{2}(4 + 6) \times 4 = 20 \text{ in}^2.

Explanation

Why wrestle with tricky fractions or decimals when a good guess will do? For a quick estimate, round each dimension—like the bases and height of a trapezoid—to the nearest whole number or an easy-to-use value. Then, plug these friendly numbers into the area formula. You'll get a speedy, 'close-enough' answer without the headache.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Lessons 71-80, Investigation 8

  1. Lesson 1

    Lesson 71: Finding the Whole Group When a Fraction is Known

  2. Lesson 2

    Lesson 72: Implied Ratios

  3. Lesson 3

    Lesson 73: Multiplying and Dividing Positive and Negative Numbers

  4. Lesson 4

    Lesson 74: Fractional Part of a Number, Part 2

  5. Lesson 5Current

    Lesson 75: Area of a Complex Figure, Area of a Trapezoid

  6. Lesson 6

    Lesson 76: Complex Fractions

  7. Lesson 7

    Lesson 77: Percent of a Number, Part 2

  8. Lesson 8

    Lesson 78: Graphing Inequalities

  9. Lesson 9

    Lesson 79: Estimating Areas

  10. Lesson 10

    Lesson 80: Transformations

  11. Lesson 11

    Investigation 8: Probability and Odds, Compound Events, Experimental Probability

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Area of a Complex Figure, Area of a Trapezoid

New Concept

To find the area of a trapezoid, we use the average of its parallel bases and its height. The textbook provides two equivalent formulas for this.

Area of a Trapezoid

extArea=extaverageofthebases×extheight ext{Area} = ext{average of the bases} \times ext{height}
A=12(b1+b2)h A = \frac{1}{2}(b_1 + b_2)h

What’s next

Next, you'll apply these formulas in worked examples involving both trapezoids and more complex figures. We will also practice estimation strategies for quick calculations.

Section 2

Area of a complex figure

Property

To find the area of a complex figure, divide it into simpler shapes (like rectangles and triangles) and add their individual areas. Alternatively, enclose the figure in a larger rectangle and subtract the areas of the parts that are not included.

Examples

  • Method 1 (Addition): Divide the figure into a 5×85 \times 8 rectangle and a triangle with base 4 and height 8. Area = (5×8)+12(4×8)=40+16=56 units2(5 \times 8) + \frac{1}{2}(4 \times 8) = 40 + 16 = 56 \text{ units}^2.
  • Method 2 (Subtraction): Enclose the figure in a 12×1212 \times 12 square and subtract a 5×85 \times 8 triangle. Area = (12×12)12(5×8)=14420=124 units2(12 \times 12) - \frac{1}{2}(5 \times 8) = 144 - 20 = 124 \text{ units}^2.

Explanation

To find the area of a funky-shaped figure, slice it up into familiar shapes like rectangles and triangles. Calculate the area of each piece, then add them all up for the grand total! Alternatively, you can frame the figure inside a big rectangle and subtract the areas of the leftover bits you don't need.

Section 3

Area of a trapezoid

Property

To find the area of a trapezoid, multiply the average of the bases by the height. The formula is:

A=12(b1+b2)hA = \frac{1}{2}(b_1 + b_2)h

Examples

  • A trapezoid has bases b1=8b_1 = 8 cm and b2=12b_2 = 12 cm, and height h=5h = 5 cm. Area = 12(8+12)×5=12(20)×5=50 cm2\frac{1}{2}(8 + 12) \times 5 = \frac{1}{2}(20) \times 5 = 50 \text{ cm}^2.
  • Find the area of a trapezoid with bases of 11 m and 15 m and a height of 8 m. Area = 12(11+15)×8=12(26)×8=104 m2\frac{1}{2}(11 + 15) \times 8 = \frac{1}{2}(26) \times 8 = 104 \text{ m}^2.

Explanation

A trapezoid has two different parallel sides, so which one do we use? Neither! The trick is to find the average of the two bases, then multiply that average by the height. This clever shortcut transforms the trapezoid into a simple rectangle with the same area, making the calculation super straightforward and avoiding any guesswork.

Section 4

Estimate Area

Property

To estimate the area of a figure, first round its dimensions (like base and height) to the nearest convenient numbers. Then, use these rounded numbers to perform the area calculation for a quick approximation.

Examples

  • Estimate the area of a trapezoid with bases 4.94.9 ft and 8.28.2 ft and height 5.85.8 ft. Round to bases 5 and 8, height 6. Area 12(5+8)×6=39 ft2\approx \frac{1}{2}(5 + 8) \times 6 = 39 \text{ ft}^2.
  • Estimate the area of a book cover with parallel sides 3783 \frac{7}{8} in. and 6186 \frac{1}{8} in. and a height of 4 in. Round bases to 4 and 6. Area 12(4+6)×4=20 in2\approx \frac{1}{2}(4 + 6) \times 4 = 20 \text{ in}^2.

Explanation

Why wrestle with tricky fractions or decimals when a good guess will do? For a quick estimate, round each dimension—like the bases and height of a trapezoid—to the nearest whole number or an easy-to-use value. Then, plug these friendly numbers into the area formula. You'll get a speedy, 'close-enough' answer without the headache.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Lessons 71-80, Investigation 8

  1. Lesson 1

    Lesson 71: Finding the Whole Group When a Fraction is Known

  2. Lesson 2

    Lesson 72: Implied Ratios

  3. Lesson 3

    Lesson 73: Multiplying and Dividing Positive and Negative Numbers

  4. Lesson 4

    Lesson 74: Fractional Part of a Number, Part 2

  5. Lesson 5Current

    Lesson 75: Area of a Complex Figure, Area of a Trapezoid

  6. Lesson 6

    Lesson 76: Complex Fractions

  7. Lesson 7

    Lesson 77: Percent of a Number, Part 2

  8. Lesson 8

    Lesson 78: Graphing Inequalities

  9. Lesson 9

    Lesson 79: Estimating Areas

  10. Lesson 10

    Lesson 80: Transformations

  11. Lesson 11

    Investigation 8: Probability and Odds, Compound Events, Experimental Probability